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spin [16.1K]
3 years ago
12

Rewrite 5/3 with a denominator of 12

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

20/12

hope this helps

have a good day :)

Step-by-step explanation:

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1/2= ?/30 what is the number missing?
KIM [24]

Answer:

15/30

Step-by-step explanation:

Simple just find out what half of 30 is, which is 15. Hope this helped you.

5 0
3 years ago
What is the missing value for y?<br><br> a.)62<br> b.)60<br> c.)38<br> d.)21
lara [203]

Answer:

87458616189741561487489

Step-by-step explanation:

87456126158648456+78484561-20515=5484156

6 0
3 years ago
The point (2, 5) is represented on the graph. Which point also belongs on this graph?
Bas_tet [7]

Can you please attach the graph?

8 0
3 years ago
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Juan sells 2 sizes of dried wreaths it takes him 3 hours to make each large and 2 hours to make each small one. he has material
Karo-lina-s [1.5K]

Answer:  The answer is (2,9) and (6,3).


Step-by-step explanation: Given that Juan sells 2 sizes of dried wreaths. He takes 3 hours to make each large one and tales 2 hours to make each small one. Also, he has material for maximum 6 large wreaths or maximum 9 small wreaths.

Let, 'x' and 'y' be the number of number of large wreaths and number of small wreaths respectively made by Juan.

So, according to the given information, we have the following relations -

3x+2y\leq 24,~~x\leq 6,~~y\leq 9.

We tried plotting these inequalities in the graph paper (please see the attached figure), and found that the following two solutions will fit the situation perfectly.

Point A (x = 2, y = 9)   and   point B (x = 6, y = 3).

Thus, the two possible combinations are

(i) 2 large wreaths and 9 small wreaths, and

(ii) 6 large wreaths and 3 small wreaths.


7 0
4 years ago
2√m^2 if m is greater than or equal to 0
iris [78.8K]

Answer:

\displaystyle  \boxed{|2m| }

Step-by-step explanation:

we are given that

\displaystyle 2 \sqrt{  {m}^{2} }

since m is greater than or equal to 0 it's a positive number therefore, the square root of m is defined and recall that √x²=|x| thus

\displaystyle  \boxed{2 |m|}

remember that,|a|•|x|=|ax| hence,

\displaystyle  \boxed{ |2m|}

and we're done!

3 0
3 years ago
Read 2 more answers
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