Solution:
As we have to write an expression , which evaluates to true if the value of the integer variable x is divisible (with no remainder) by the integer variable y, y≠0.
so, when x is divided by y we should get remainder as 0.
Using Euclid division lemma
x= y* q + m, i.e when an integer x is divided by y gives quotient q and remainder m.
Here , m=0
So, x = q * y
So, the expression which describes the above relationship is ,
, where q is Quotient.
Answer:
(x, y) = (2, 9)
Step-by-step explanation:
For the triangles to be congruent, the hypotenuses must be the same length:
y = x + 7
and the marked leg must be the same length in each triangle:
y -3 = 4x -2
These are two equations in two unknowns (a "system" of equations) that can be solved in any of the usual ways. Since the first equation gives an expression for y, it is convenient to substitute that into the second equation:
(x +7) -3 = 4x -2
x +4 = 4x -2 . . . . . . collect terms
x +6 = 4x . . . . . . . . .add 2
6 = 3x . . . . . . . . . . . subtract x
2 = x . . . . . . . . . . . . divide by 3
y = 2 + 7 = 9 . . . . . .substitute for x in the first equation
The values you're looking for are x = 2, y = 9.
Answer:
200
Step-by-step explanation:
of an amount is 30. Calculate the whole amount using two different strategies, one of which must include a pictorial model. 15% = = The whole quantity is 200.
Answer:
number of ways = 120
Step-by-step explanation:
The number of ways five children can pose for a photograph line up in a row is given by the number of permutations of 5 elements in 5 different positions (positions in the line), then
number of ways = number of permutations of 5 elements = 5! = 5 * 4 * 3 * 2 * 1 = 120
Since the first children that occupies the line can be on any of the positions (5 positions) , but then the second one can choose any of the 4 remaining positions (since the first children had already occupied one) , the third can choose 3 ... and so on.
