N= -20/133
Step 1: Simplify both sides of the equation.
−
2
(
−
4
n
+
1
)
+
5
(
25
n
−
8
)
=
−
62
(
−
2
)
(
−
4
n
)
+
(
−
2
)
(
1
)
+
(
5
)
(
25
n
)
+
(
5
)
(
−
8
)
=
−
62
(Distribute)
8
n
+
−
2
+
125
n
+
−
40
=
−
62
(
8
n
+
125
n
)
+
(
−
2
+
−
40
)
=
−
62
(Combine Like Terms)
133
n
+
−
42
=
−
62
133
n
−
42
=
−
62
Step 2: Add 42 to both sides.
133
n
−
42
+
42
=
−
62
+
42
133
n
=
−
20
Step 3: Divide both sides by 133.
133
n
133
=
−
20
133
n
=
−
20
133
Answer:
x = i π n + log(20)/2 for n element Z
Step-by-step explanation:
Solve for x:
500 = 25 e^(2 x)
500 = 25 e^(2 x) is equivalent to 25 e^(2 x) = 500:
25 e^(2 x) = 500
Divide both sides by 25:
e^(2 x) = 20
Take the natural logarithm of both sides:
2 x = 2 i π n + log(20) for n element Z
Divide both sides by 2:
Answer: x = i π n + log(20)/2 for n element Z
1st box:
m<A + m<B + m<C = 180
2nd box:
substitution property
3rd box:
division property of equality
Hope it helps.
Answer:
WV is the perpendicular bisector of UT.
Answer:
1/12
Step-by-step explanation:
multiple of 3 and a multiple of 4 implies it can only be 12.
Since you only have the numbers from 1 to 12,
the prob(the 12) = 1/12
