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3 years ago

What is 3 root of − 216 end root

1 answer:

7 0

I believe you are asking for the cubic root of 216; this means "What times itself 3 times would equal 216?".

The answer is 6:

6x6x6=216

To break it down further:

6x6=36
36x6=216

I Hope this Helps!

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Need some help with this one please

Airida [17]

Answer: Choice A

y = (-3/4)(x + 4) + 6

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Let's go through the answer choices

Choice A is something we'll come back to
Choice B is false because the line does not go uphill as we move from left to right. The graphed line has a negative slope, which contradicts what choice B is saying.
Choice C is false for similar reasons as choice B. The slope should be negative.
Choice D has a negative slope, but the y intercept is wrong. The y intercept should be 3. So choice D is false as well.

We've eliminated choices B through D.

Choice A must be the answer through process of elimination.

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Here's an alternative method:

If we started at a point like (0,3) and move to (4,0), note how the slope is -3/4

This is because we've moved down 3 units and to the right 4 units.

m = slope = rise/run = -3/4

We can also use the slope formula m = (y2-y1)/(x2-x1) to see this.

Then we pick on a point that is on the diagonal line. It could be any point really, but the point your teacher used for choice A is (x1,y1) = (-4,6)

So,

y - y1 = m(x - x1)

y - 6 = (-3/4)(x - (-4))

y - 6 = (-3/4)(x + 4)

y = (-3/4)(x + 4) + 6

7 0

3 years ago

The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough

liberstina [14]

Answer:

a) $t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

$\bar X=1175$ represent the sample mean for the cubic feets of households

$\sigma=250$ represent the population standard deviation

$n=100$ sample size

$\mu_o =1425$ represent the value to verify

$\alpha=0.025$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1425$

Alternative hypothesis: $\mu < 1425$

Since we don't know the deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0

3 years ago

An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre

Shtirlitz [24]

Answer:

Null Hypothesis, $H_0$ : $\mu \leq$ 250 W