Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

Hence the bounds of the interval are found as follows:


The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
The answer is
A.
Hope This Helps
Answer:
10 <
< 11
Step-by-step explanation:
The square root of 111 is approximately 10.536.
A number smaller than this is 10.
A number larger than this is 11.
Answer:
The answer is 17
Step-by-step explanation:
8^2+15^2=c^2
64+225=c^2
289=c^2
Square root both sides
c=17