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ryzh [129]
3 years ago
10

One and five twelves minus five sixtes

Mathematics
1 answer:
erica [24]3 years ago
4 0

Answer: 5/12

Step-by-step explanation: 5/12

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Find the slope of the line<br>A -20 <br>B 0 <br>C 1 <br>D Undefined​
sweet [91]

Answer:  it's B  because  i tried C, and A, and i know it's not D

i hope this helped you

3 0
3 years ago
at the pet fair,darlene's dog weighed 5 times as much as leah's dog.together the dog weighed 84 pounds. how much did each dog we
Sati [7]
It is 420 because your doing 5 x 84
5 0
3 years ago
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A 3-foot wife wood deck will be built around rectangular shaped pool that measures 15feet by 30feet. The resulting shape is also
lisov135 [29]

Answer:

$340

Step-by-step explanation:

The pool is 5 yards wide by 10 yards long, so adding the deck will make the total area 7 yards wide by 12 yards long, or ...

(7 yd)·(12 yd) = 84 yd^2

The pool itself is ...

(5 yd)·(10 yd) = 50 yd^2

so the area of the deck is ...

84 yd^2 -50 yd^2 = 34 yd^2

Wood for each of those square yards costs $10, so the total cost is ...

($10/yd^2)·(34 yd^2) = $340

6 0
3 years ago
ben needs to convert 500 US dollars to the japanese yen. one american dollar is worth 123.3 yen. how many yen will he have
laiz [17]

Answer:

<u>The correct answer is 61,650 Yens</u>

Step-by-step explanation:

US$ in cash that Ben has = 500

Exchange rate (US$/Yen) = 1 : 123.3

For calculating the total amount in Yens that Ben has, we use this formula:

Yens in Cash = US$ in Cash * Exchange rate given

Yens in Cash = 500 * 123.3

Yens in Cash = 61,650

<u>After converting the US$ 500 Ben has, he will receive Yens 61,650</u>

6 0
3 years ago
A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t
Tomtit [17]

Answer:

0.54\,\,m^3

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × \frac{1.2}{2}=0.6\,\,m (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= 0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6

=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3

4 0
3 years ago
Read 2 more answers
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