All scalar multiples of the vector [ 4, 5] makes the
line y = 5/4 x.
The matrix A of the orthogonal projection onto the line L is made of the
coordinates of the projections of the base trajectories i and j onto the line L
printed in columns.
The line L: y = 5/4*x
Orthogonal line passing over the point (1, 0): y = -4/5 *x + 4/5
Point of Intersection: (16/41, 21/41)
Projections: P(i) = 16/41 i + 21/41 j, P(j) = 16/41 i + 21/41 j
The matrix:
A = || 16/41..16/41||
......|| 16/41....16/41 ||
Answer:
4^4
Step-by-step explanation:
Working from left to right
4^5 * 4^-7 ÷ 4^-2
We know that a^b * a^c = a^(b+c)
4^5 * 4^-7 = 4^(5-7) = 4^2
4^2 ÷ 4^-2
We know a^b / a^c = a^(b-c)
4^2 ÷ 4^-2 = 4^(2- -2) = 4^(2+2) = 4^4
y= 3/8 OR 0.375
Step-by-step explanation:
yes
$10.5
Your car would cost a total of $25.5 to get to Detroit. and your friends car would cost $15.5. So you end up saving a total amount of $10.50