What is the missing term? -4.-12.x 12.-4 . 2x ? 2.2 3х +1

5.6.AP-1 Solve the inequality. 3 + 4x> 27

iren [92.7K]

Answer:

The answer is X>6

if you click the image it will show the steps to solving the inequality. hope this helps.

8 0

3 years ago

A highschool had 740 students at the start of the year but then some students left the school after that the school had 726 stud

iris [78.8K]

The mathematical sentance would be, 740 - 14 = 726, hope this helps.:D

8 0

3 years ago

I don’t get 1 2 3 and 4

g100num [7]

The picture shows 5 groups of 3 bars. Each bar represents 1/10. We take the picture to mean that ...

... (15/10) / 5 = 3/10

In decimal:

... 1.5 / 5 = 0.3

The picture shows 3 groups of 2 bars. Each bar represents 1/10. We take the picture to mean that ...

... (6/10) / 3 = 2/10

In decimal:

... 0.6 / 3 = 0.2

The picture shows 4 groups, each consisting of 1 large square, 1 bar, and 4 small squares. We take the picture to mean that ...

... (4 + 4/10 + 16/100) / 4 = 1 + 1/10 + 4/100

In decimal:

... 4.56 / 4 = 1.14

Please note that 16/100 is equivalent to 1/10 + 6/100. In order to do the division, one of the 1/10 bars needed to be changed into 10 small squares, 10/100.

The picture shows 3 groups, each consisting of 1 large square, 3 bars, and 2 small squares. We take the picture to mean that ...

... (3 + 9/10 +6/100) / 3 = 1 +3/10 + 2/100

In decimal:

... 3.96 / 3 = 1.32

6 0

3 years ago

What is an equation of the line that passes through the point (3,6)(3,6) and is parallel to the line 4x-3y=214x−3y=21?

polet [3.4K]

Question:

What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21

Answer:

The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:

$y = \frac{4}{3}x + 2$

Solution:

Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21

The equation of line in slope intercept form is given as:

y = mx + c ------- eqn 1

Where, "m" is the slope and "c" is the y intercept

Given equation is:

4x - 3y = 21

Rearrange,

3y = 4x - 21

$y = \frac{4}{3}x - \frac{21}{3}\\\\y = \frac{4}{3}x - 7$

On comparing above equation with eqn 1,

$m = \frac{4}{3}$

We know that slopes of parallel lines are same

Therefore, slope of line parallel to the line 4x - 3y = 21 is 4/3

Substitute m = 4/3 and (x, y) = (3, 6) in eqn 1

$6 = \frac{4}{3} \times 3 + c\\\\6 = 4 + c\\\\c = 2$

Substitute c = 2 and m = 4/3 in eqn 1

$y = \frac{4}{3}x + 2$

Thus the equation of line is found

4 0

4 years ago

Find the equation of the directrix of the parabola x2=+/- 12y and y2=+/- 12x

PIT_PIT [208]

Answer:

x^2 = 12 y equation of the directrix y=-3
x^2 = -12 y equation of directrix y= 3
y^2 = 12 x equation of directrix x=-3
y^2 = -12 x equation of directrix x= 3

Step-by-step explanation:

To find the equation of directrix of the parabola, we need to identify the axis of the parabola i.e, parabola lies in x-axis or y-axis.

We have 4 parts in this question i.e.

x^2 = 12 y
x^2 = -12 y
y^2 = 12 x
y^2 = -12 x

For each part the value of directrix will be different.

For x² = 12 y

The above equation involves x² , the axis will be y-axis

The formula used to find directrix will be: y = -a

So, we need to find the value of a.

The general form of equation for y-axis parabola having positive co-efficient is:

x² = 4ay eq(i)

and our equation in question is: x² = 12y eq(ii)

By putting value of x² of eq(i) into eq(ii) and solving:

4ay = 12y

a= 12y/4y

a= 3

Putting value of a in equation of directrix: y = -a => y= -3

The equation of the directrix of the parabola x²= 12y is y = -3

For x² = -12 y

The above equation involves x² , the axis will be y-axis

The formula used to find directrix will be: y = a

So, we need to find the value of a.

The general form of equation for y-axis parabola having negative co-efficient is:

x² = -4ay eq(i)

and our equation in question is: x² = -12y eq(ii)

By putting value of x² of eq(i) into eq(ii) and solving:

-4ay = -12y

a= -12y/-4y

a= 3

Putting value of a in equation of directrix: y = a => y= 3

The equation of the directrix of the parabola x²= -12y is y = 3

For y² = 12 x

The above equation involves y² , the axis will be x-axis

The formula used to find directrix will be: x = -a

So, we need to find the value of a.

The general form of equation for x-axis parabola having positive co-efficient is:

y² = 4ax eq(i)

and our equation in question is: y² = 12x eq(ii)

By putting value of y² of eq(i) into eq(ii) and solving:

4ax = 12x

a= 12x/4x

a= 3

Putting value of a in equation of directrix: x = -a => x= -3

The equation of the directrix of the parabola y²= 12x is x = -3

For y² = -12 x

The above equation involves y² , the axis will be x-axis

The formula used to find directrix will be: x = a

So, we need to find the value of a.

The general form of equation for x-axis parabola having negative co-efficient is:

y² = -4ax eq(i)

and our equation in question is: y² = -12x eq(ii)

By putting value of y² of eq(i) into eq(ii) and solving:

-4ax = -12x

a= -12x/-4x

a= 3

Putting value of a in equation of directrix: x = a => x= 3

The equation of the directrix of the parabola y²= -12x is x = 3

5 0

3 years ago