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1 year ago

6(8f+10g) + 9g - 4(3g+9f)

Mathematics

1 answer:

Karolina [17]1 year ago

8 0

Answer:84f+57g

Step-by-step explanation:

First, multiply everything in parenthesis.

Multiply the 6 by 8f+10g, and the 4 by 3g+9f.

This gets you 48f+60g+9g-12g+36f.

After that, just solve it like normal.

You get 84f+57g.

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URGENT HELPPP !!!!!! Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!

GaryK [48]

Answer:

(8,-3)

Step-by-step explanation:

I just added 1 to the x value and added 2 to the y value because that was the difference between point A and the midpoint of the segment.

Hope this helps!

3 0

2 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago

Arrange these numbers from least to greatest:

zmey [24]

First let's put them all over 100.
- $\frac{5}{8}$ would change to - $\frac{62.5}{100}$

- $\frac{7}{9}$ to - $\frac{77.7}{100}$

- $\frac{4}{5}$ to - $\frac{80}{100}$

- $\frac{3}{7}$ to - $\frac{42.8}{100}$

Then if we put them from least to greatest it would be from highest to lowest (since they are negatives)

- $\frac{4}{5}$ , - $\frac{7}{9}$ , - $\frac{5}{8}$ , - $\frac{3}{7}$

The answer would be B

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3 years ago

When their report cards came back, Pete, Chris, and Dina realized that they shared the number of A’s in the ratio 4:2:5. If Pete

ankoles [38]

15 I believe.. I could be wrong bc idk if youre adding the A's to the ratio or starting at 0

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3 years ago

(21-4i)-(16-7i)+28i in standard form

lara [203]

Your answer in standard form would be 5+31i

4 0

3 years ago