A triangular prism and two nets are shown :

Whitepunk [10]

Hey there,

The first thing you have to do is add -1y to both sides:
1x + 1y = 8
+-1y +-1y

You should get: 1x = -1y+8

So your total answer is: 1x = -1y+8

~~I hope I helped and let me know if you need anything else~~

Latis1218

7 0

3 years ago

Which is the same as diving a number by 10?

Licemer1 [7]

Answer:

Step-by-step explanation:

well i guess if the decimal is on the left you would move it to the right twice

because if you only moved it once it'd become 1.0

and if you moved it to the left once it would also become 1.0

and if you moved it twice to the left you would be left with .10

pls mark me brainliest

7 0

3 years ago

What goes in the boxes ig?

lana [24]

To convert 1.07 to a fraction, multiply it by 100.

1.07 * 100 = 107

So the percent equivalent of 1.07 is 107%.

Just put 1.07 over 100 to turn it into a fraction.

107/100 would be the fraction equivalent.

7 0

2 years ago

Consider the probability that greater than 26 out of 124 software users will call technical support. Assume the probability that

Mekhanik [1.2K]

Answer:

Since $n(1-p) = 3.72 < 10$ , the normal curve cannot be used as an approximation to the binomial probability.

100% probability that greater than 26 out of 124 software users will call technical support.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

$np \geq 10$ and $n(1-p) \geq 10$

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Out of 124 software users

This means that $n = 124$

Assume the probability that a given software user will call technical support is 97%.

This means that $p = 0.97$

Conditions:

$np = 124*0.97 = 120.28 \geq 10$

$n(1-p) = 124*0.03 = 3.72 < 10$

Since $n(1-p) = 3.72 < 10$ , the normal curve cannot be used as an approximation to the binomial probability.

Consider the probability that greater than 26 out of 124 software users will call technical support.

The lowest possible probability of those is 27, so, if it is 0, since it is considerably below the mean, 100% probability of being greater. We have that:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 27) = C_{124,27}.(0.97)^{27}.(0.03)^{97} = 0$

1 - 0 = 1

100% probability that greater than 26 out of 124 software users will call technical support.

3 0

3 years ago

Help! Please! <br> Factor the polynomial completely.<br> 32z^5-2z

Sever21 [200]

Answer:

2z(4z^2+1)(2z+1)(2z-1)

Step-by-step explanation:

here is just some basic polynomial factoring where you find something both the numbers have in common and you take that out of the equation. here i just went a little bit deeper and after taking out the common factor i also expanded my answer further as this would be the fully correct answer.

hope this helps!

5 0

2 years ago

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