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pickupchik [31]
3 years ago
8

Select two ratios that are equivalent to 4:18

Mathematics
1 answer:
fredd [130]3 years ago
8 0

36:8, 9:2, and 72: 16

Step-by-step explanation:

two ratios that are equivalent to 4:18

36:8, 9:2, and 72: 16

would all be equivalent. In order to find ratios that are equivalent to 18:4, you have to multiply both numbers by the same factor. For

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A university needed to transport 90 fans to its football game from the stadium parking lot. The university rented a bunch of van
andrew-mc [135]

Answer:

90 divided by 10

Step-by-step explanation:

This is the answer because when you divide the 90 and the amount of students in each van(10) you would get the equation needed to see how many students are in each van.

3 0
4 years ago
How much cardboard needed to construct a rectangular prism measuring 15 inches by 13 inches by 7 inches
aleksandrvk [35]
1,365

hopefully, this helps

4 0
3 years ago
Solve For 1/4 + 1/2 + x = - 3/4
ivann1987 [24]

Answer:

x= negitive 6/8

Step-by-step explanation:

Ok think about it 1/4 plus 1/2 is 3/4

so how do i go to negitives?

you double the amount of it and then minus it

because 3/4- 3/4 would be zero

so you have to double it to get that answer

have a wonderful day filled with only joy!

5 0
3 years ago
Create an equivalent expression for 9(5x - 4) by using the distributive property.
Bogdan [553]

Answer:

3(15x-12)

Step-by-step explanation:

4 0
3 years ago
1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel
Lana71 [14]

Answer:

a)  \overline{AB} = 8 in

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. \overline{AB} = 10 in

c)  When the length of AB = 10.2 in. and BC = 3.7 in.  \overline {AC}  = 6.5 in

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. \overline {BC} =  1\frac{1}{2} in

Step-by-step explanation:

a) When the length of AC = 5 in. and CB = 3 in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 5 in. + 3 in. = 8 in.

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 6\frac{1}{2} in.+ 3\frac{1}{2} in. = 10 in.

c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;

The length of \overline {AC} = AB - BC (converse of the segment addition postulate)

Therefore;

\overline {AC} = 10.2 in.+ 3.7 in. = 6.5 in.

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. we have;

The length of \overline {BC} = AB - AC (converse of the segment addition postulate)

Therefore;

\overline {BC} = 4\frac{3}{4} in. -  3\frac{1}{4} in.=  1\frac{1}{2} in.

6 0
3 years ago
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