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nikitadnepr [17]
2 years ago
11

A student's tuition was $3000. A loan was obtained for 5/6 of the tuition. How much was the loan?

Mathematics
1 answer:
Marina86 [1]2 years ago
8 0
Answer: 2,500

5/7 of 3500 = (5/7)*(3500)

5/7 of 3500 = (5/7)*(3500/1)

5/7 of 3500 = (5*3500)/(7*1)

5/7 of 3500 = (17500)/(7)

5/7 of 3500 = 2500
Hope this helped:)
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Write and solve a system of equations: Vanessa and Geneva worked together to buy a pair of tickets ($240 total) to the Green Day
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Answer:

The systems of equation are \left \{ {{v+g=21} \atop {10v+12g=240}} \right..

Vanessa worked for<u> 6 hrs </u>and Geneva worked for <u>15 hrs</u> to earn exactly $240.

Step-by-step explanation:

Let the number of hours worked by Vanessa be 'v'.

Let the number of hours worked by Geneva be 'g'.

Given:

Total number of hours worked = 21 hours

So we can say that;

Total number of hours worked is equal to sum of number of hours worked by Vanessa and number of hours worked by Geneva.

framing in equation form we get;

v+g=21              ⇒ equation 1

Also given:

per hour earnings of Vanessa = $10

per hour earning of Geneva = $12

Total they need to earn = $240

So we can say that;

Total they need to earn would be equal to sum of  per hour earnings of Vanessa multiplied by number of hours worked by Vanessa and per hour earning of Geneva multiplied by number of hours worked by Geneva.

framing in equation form we get;

10v+12g =240     ⇒ equation 2

Hence The systems of equation are \left \{ {{v+g=21} \atop {10v+12g=240}} \right..

On Solving above equations we get;

First we will multiply equation 1 by 10 we get;

10(v+g)=21\times10

10v+10g =210     ⇒ equation 3

Now Subtracting equation 3 from equation 2 we get;

10v+12g -(10v+10g)=240-210\\\\10v+12g-10v-10g=30\\\\2g =15

Dividing both side by 2 we get;

\frac{2g}{2}=\frac{30}{2}\\\\g =15\ hrs

Now Substituting the value of g in equation 1 we get;

v+g=21\\\\v+15=21\\\\v=21-15 =6\ hrs

Hence Vanessa worked for<u> 6 hrs </u>and Geneva worked for <u>15 hrs</u> to earn exactly $240.

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