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Vladimir [108]
1 year ago
8

Which number line shows the solution to the inequality 5 ≤ 8-3x ≤ 14?

Mathematics
1 answer:
katen-ka-za [31]1 year ago
5 0

The number line 5 ≤ 8-3x  shows the solution to the inequality as x cannot be more than 1.

<h3>What is inequality?</h3>

A inequality compares two values and indicates whether one is smaller, larger, or simply not equal to the other.

a  ≠ b is the information that a and b are not equal.

If a  > b, a is greater than b. (these two are defined as strict inequality)

a ≤ b proves that a is less than or equal to b

a ≥ b proves that a is greater than or equal to b

The number line 5 ≤ 8-3x  shows the solution to the inequality as x cannot be more than 1.

If x is more than 1, lets say 2

Then the inequality as follows

5 ≤ 8-3(2) ≤ 14

5 ≤ 8-6 ≤ 14

5 ≤ 2 ≤ 14  this statement becomes false

Therefore x, must be lower than 1

Learn more about inequality

brainly.com/question/24372553

#SPJ10

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No, a convenience sample was taken.Therefore, the sample may not be representative of all college students in terms of number of hours studied per week.

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One of the important conditions required in other to estimate the mean of the population from the confidence interval. Requires that the data must be a random Sample. This is to ensure that sample values are not biased and as such are representative of the larger group of data.

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A sphere has a volume of 18,432π cubic feet. What is the radius of the sphere?
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4 years ago
The diameters of a batch of ball bearings are known to follow a normal distribution with a mean 4.0 in and a standard deviation
8_murik_8 [283]

Answer:

a) 88.54% probability of a diameter between 3.8 in and 4.3 in

b) 25.14% probability of a diameter smaller than 3.9in

c) 90.82% probability of a diameter larger than 4.2 in

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4, \sigma = 0.15

(a) a diameter between 3.8 in and 4.3 in,

This is the pvalue of Z when X = 4.3 subtracted by the pvalue of Z when X = 3.8.

X = 4.3

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.3 - 4}{0.15}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 3.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.8 - 4}{0.15}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918

0.9772 - 0.0918 = 0.8854

88.54% probability of a diameter between 3.8 in and 4.3 in

(b) a diameter smaller than 3 9 in,

This is the pvalue of Z when X = 3.9. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.9 - 4}{0.15}

Z = -0.67

Z = -0.67 has a pvalue of 0.2514

25.14% probability of a diameter smaller than 3.9in

(c) a diameter larger than 4.2 in

This is 1 subtracted by the pvalue of Z when X = 4.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.2 - 4}{0.15}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

90.82% probability of a diameter larger than 4.2 in

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