All categories

3 years ago

1-7 blanks it’s due at 12 am plz help!

Mathematics

1 answer:

dexar [7]3 years ago

5 0

X-int: (square root of 31 + 6,0) & (square root of 31-6,0)

Y-int: (0,5)
Vertex: (6,-31)
AOS: x=6
Max/Min Value: (6,-31)

You might be interested in

look at the figure shown below which step should be used to prove that point a is equidistant from points c and b

JulijaS [17]

D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.

C
is wrong as well. The triangles might be similar, but they are more. They are congruent.

B
You don't have to prove that. It is given on the way the diagram is marked.

A
A is your answer. The two triangles are congruent by SAS

3 0

3 years ago

Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-

Korolek [52]

Since each vector is a member of $\mathbb R^3$ , the vectors will span $\mathbb R^3$ if they form a basis for $\mathbb R^3$ , which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors $c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3$ that gives the zero vector $\mathbf0$ occurs for scalars $c_1=c_2=c_3=0$ .

$c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}$

Solving this, you'll find that $c_1=c_2=c_3=0$ , so the vectors are indeed linearly independent, thus forming a basis for $\mathbb R^3$ and therefore they must span $\mathbb R^3$ .

4 0

3 years ago

(07.03)

Mkey [24]

x = 2

5(2 • 2 - 6) + 20

5(2x - 6 )+ 20 = 10

10x - 30 + 20 = 10

10x - 10 = 10

+10 +10

10 / 10x = 20 / 10

x = 2

7 0

3 years ago

What is the sum of the measures of the interior angles of the decagon?

ololo11 [35]

Given parameters:

Number of sides of the regular body = 10

A decagon has 10 sides.

Unknown:

Sum of the measures of the interior angles = ?

Solution;

To find the sum of the interior angles of a decagon; use the expression below:

Sum of interior angles = (n - 2) x 180

where;

n = number of sides;

So,

Sum of interior angles = (10 - 2) x 180 = 1440°

The sum of interior angle of a decagon is 1440°

6 0

3 years ago

18% top for a $30 meal

irakobra [83]

Answer:

the end is 24.6 because 30-18% is equal to 24.6

4 0

3 years ago