All categories

2 years ago

1-7 blanks it’s due at 12 am plz help!

Mathematics

1 answer:

dexar [7]2 years ago

5 0

X-int: (square root of 31 + 6,0) & (square root of 31-6,0)

Y-int: (0,5)
Vertex: (6,-31)
AOS: x=6
Max/Min Value: (6,-31)

You might be interested in

Find the 10th term of the sequence defined by the rule, f (n) = 4n - 3.

DiKsa [7]

Answer:

Step-by-step explanation:

f(n) = 4n - 3

f(10) = 4×10 - 3 = 40 - 3 = 37

6 0

3 years ago

C=27+10h where c= cost in dollars and h= number of hours rented

gavmur [86]

Answer:

that help

Step-by-step explanation:

10h+27+−27=c+−27

10h=c−27

10h10=c−2710

h=110c+−2710

Answer:

h=110c+−2710

3 0

2 years ago

What set of transformations is performed on ABCD to form A′B′C′D′?

Ilia_Sergeevich [38]

Reflection across the y-axis, one unit down, one unit to the right.

Hope It Helps!

7 0

2 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

2 years ago

The most recent census for a city indicated that there were 919,716 residents. The population of the city is expected to increas

OLEGan [10]

Answer:

1,474,951.

Step-by-step explanation:

Given a population that increases by a constant percentage, we can model the population's growth using the exponential model.

$P(t)=P_o(1+r)^t,$ where \left\{\begin{array}{lll}P_o=$Initial Population\\r$=Growth rate\\$t=time (in years)\end{array}\right\\P_o=919,716\\r=3.7\%=0.037\\$t=13 years$

Therefore, the population of the city in 13 years time will be:

$P(t)=919,716(1+0.037)^{13}\\\\=919,716(1.037)^{13}\\\\=1,474,950.9\\\\\approx 1,474,951$

The population be at that time will be approximately 1,474,951.

3 0

3 years ago