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1 year ago

4•12 compared to 8•6

Mathematics

1 answer:

olga2289 [7]1 year ago

6 0

When 4•12 is compared to 8•6, it can be concluded that →

4 • 12 = 8 • 6.

<h3>What is Comparison in Mathematics?</h3>

Comparison in mathematics is used to compare two numbers or expressions in order to find which number or expression is greater or small.

Following symbols are used for comparison →

> (greater than)

< (less than)

≥ (greater than or equal to)

≤ (less than or equal to)

= (equal to)

Given is the following statement - 4•12 compared to 8•6.

In order to compare both expressions, first we will have to simplify them-

4 • 12 = 48

8 • 6 = 48

Now, if we compare both the expressions, we can conclude that both are equal.

Therefore, when 4•12 is compared to 8•6, it can be concluded that →

4 • 12 = 8 • 6.

To solve more questions on Number comparison, visit the link below-

brainly.com/question/28483189

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Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

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$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$

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