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kaheart [24]
3 years ago
10

A gym has three trainers, Aldo, Bertha, and Coco, who each have 1/3 of the new members. A person who trains with Aldo has a 60%

chance of being successful, a person who trains with Bertha has a 30% chance of being successful and a person who trains with Coco has a 90% chance of being successful. What is the probability that a successful member had Bertha as her trainer?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

1/10

Step-by-step explanation:

P(a successful member

had Bertha as her trainer)  = P(Bertha being you trainer) x P(being successful if

                                                trained by Bertha)

                                             = 1/3 x 30/100

                                             = 30/300

                                             = 1/10

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00:36:46
miskamm [114]

Question:

In some code, letters a, b, c, d and e represent numbers 2, 4, 5, 6 and 10. We just do not know which letter represents which number. Consider the following relationships:

a + c = e,

b – d = d and

e + a = b

Which of the following statements is true?

(A) b = 4, d = 2

(B) a = 4, e = 6

(C) b = 6, e = 2

(D) a = 4, c = 6

Answer:

(B) a = 4, e = 6 is the correct answer.

Explanation:

(A) b = 4, d = 2

a + c = e => a + c = e

b – d = d => 4 - 2 = 2

e + a = b => e + a = 4

We are not able to find out what will be at place of a , c , e by which all other relationships are not getting satisfied. And if we apply numbers by hit and trial they are not getting satisfied.

(B) a = 4, e = 6

a + c = e => 4 + c = 6 => 4 + 2 = 6

b – d = d => b - d = d => 10 - 5 = 5

e + a = b => 6 + 4 = 10

We were able to find all a , b , c , d , e and it satisfies all relationships given.

(C) b = 6, e = 2

a + c = e => a + c = 2

b – d = d => 6 - d = d

e + a = b => e + a = 6

We are not able to find out what will be at place of a , c , d by which all other relationships are not getting satisfied. And if we apply numbers by hit and trial they are not getting satisfied.

(D) a = 4, c = 6

a + c = e => 4 + 6 = 10

b – d = d => b - d = d

e + a = b => e + 4 = b => 10 + 4 = 14(this is not from the numbers as given in question so b can't be equal to 14)

We got stuck at the value of b which was 14 and not given in question so, we can leave this option in between as it is not satisfying the relationships.

Therefore, (B) a = 4, e = 6 is the correct answer.

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Which expression will make the equation true <br> -4.5+4.4+x=0
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Answer:

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Step-by-step explanation:

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