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1 year ago

What is the probability that a selected pet is a puppy given the pet is black?

Mathematics

1 answer:

vredina [299]1 year ago

4 0

please mark as brainiest

Answer:

I'm going to go with C

Step-by-step explanation:

because the puppy has to be black out of all of the pets not just the black ones thus 10/55

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WILL MAKE BRAINLIEST Determine the value of x a) 7.8 b) 4.62 c)6 d) 0.22

laiz [17]

Answer:

I came to the answer of 6.

6 0

3 years ago

There are six orange marbles, 2 red marbles, 3 white marbles, and 4 green marbles in a bag. Once a marble is drawn, it is replac

bogdanovich [222]

Answer:

2.) 2 orange marble in a raw

Step-by-step explanation:

because there are more orange marble than other colours

8 0

3 years ago

I need help ASAP...this is important to me

xenn [34]

Answer:1863

Step-by-step explanation:

How is that a complex figure lol?

anyways, It is a rectangle - a smaller rectangle.

Area of rectangle is 31 * 69.

Area of smaller rectangle is 12 * 23

31*69-12*23=1863.

7 0

3 years ago

Read 2 more answers

What is a positive minus a negative

kogti [31]

When minusing a negative, the two negative/minus signs become a positive, so it would be a positive add another positive, giving a positive number

8 0

4 years ago

exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr

Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick different colors in the first four pick.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is $\frac{6}{7}$

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is $\frac{4}{6}$

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is $\frac{2}{5}$

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1× $\frac{6}{7}$ × $\frac{4}{6}$ × $\frac{2}{5}$ ≈ 0.2286

5 0

4 years ago