Question

What would you use for the

Answer 1

The least common denominator is  $&\frac{2}{3 b q}$.

The smallest number that is precisely divisible by each denominator of a group of fractions is known as the lowest common denominator.

What is meant by least common denominator?

The lowest common multiple of the denominators of a group of fractions is known as the lowest common denominator, or LCD, in mathematics. It makes adding, taking away, and comparing fractions easier.

When two or more fractions are supplied, the least common denominator is the smallest number among all the common multiples of the denominators.

The smallest number that is precisely divisible by each denominator of a group of fractions is known as the lowest common denominator. It is occasionally referred to as the lowest common denominator.

a) $\frac{2 q}{3 b q^2}$

Apply exponent rule:

$\frac{x^a}{x^b}=\frac{1}{x^{b-a}}$

substitute the values in the above equation, we get

$&\frac{q^1}{q^2}=\frac{1}{q^{2-1}}$

simplifying the above equation, we get

$&=\frac{2}{3 b q^{2-1}}$

Subtract the numbers,

$=\frac{2}{3 b q^1}$

Apply exponent rule:

$&q^1=q$

$&=\frac{2}{3 b q}$

b) $\frac{3 b^2}{7 b^4 q}$

Apply exponent rule, we get

$\quad \frac{x^a}{x^b}=\frac{1}{x^{b-a}}$

substitute the values in the above equation, we get

$&\frac{b^2}{b^4}=\frac{1}{b^{4-2}}$

$&=\frac{3}{7 b^{4-2} q}$

Subtract the numbers:

$=\frac{3}{7 b^2 q}$

$\frac{4 q^2}{8 b^2 q^5}$

Factor the number:

$=\frac{4 q^2}{4 \cdot 2 b^2 q^5}$

Cancel the common factor,

$=\frac{q^2}{2 b^2 q^5}$

Simplifying the above equation, we get

$\frac{q^2}{q^5}: \frac{1}{q^3}$

$=\frac{1}{2 b^2 q^3}$

Therefore, the correct answer is option a) $&\frac{2}{3 b q}$.

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