The midpoints are (8,3) and (6.5,6).
<u>Step-by-step explanation</u>:
Midpoint formula = ((x1+x2)/2 , (y1+y2)/2)
(x1,y1) = (5,2)
(x2,y2) = (11,4)
Midpoint = ((5+11)/2 , (2+4)/2)
⇒ ((16/2) , (6/2))
⇒ (8,3)
(x1,y1) = (3,8)
(x2,y2) = (10,4)
Midpoint = ((3+10)/2 , (8+4)/2)
⇒ ((13/2) , (12/2))
⇒ (6.5,6)
3x+2=32 and x=10 just if you're wondering.
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Answer:
a squared plus b squared = c squared
Step-by-step explanation:
a) 100
b) 153
Honestly I'm just guessing i'm only in algebra 1 and even if i wasn't I suck at geometry
$57.60 is the correct answer