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Leokris [45]
1 year ago
6

Which relation is a function?

Mathematics
2 answers:
puteri [66]1 year ago
6 0

let's recall the vertical line test, if a vertical line hits the graph or points twice, then is NOT a function.  Check the picture below.

Liula [17]1 year ago
4 0

A very easy way to find out if a graph is a function is to use the vertical line test.

Look at each graph and mentally draw a vertical line that goes through each of its points.

If that line goes through more than one point (2, 3, 4...) then that graph is not a function.

That's because a function, is an equation for which each input (x value) has exactly one output (y value). There cannot be two points of the same x value, with two different y values.

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Use 4's and any of the operations: +, -, × and ÷ to write number sentences.
Furkat [3]

Answer:

Step-by-step explanation:

(4x4)÷(4+4) = 2

(4x4)÷ (4 +4) - 4= 4

(4+4)+(4÷ 4)-  4= 5

(4+4)- (4÷4) - 4= 3

8 0
3 years ago
Read 2 more answers
Can you help me with 7 and 8
elena55 [62]
All I know or all I understood was both 7 and 8 aren’t functions. Hope this helped
4 0
3 years ago
I need help can some please answer this 2 2/3+1 1/2
irakobra [83]

Answer:

25/6 or 4 1/6

Step-by-step explanation:

1) convert these fractions to improper fractions first:

8/3+3/2

make like denominators  by multiplying 8/3 by 2 and 3/2 by 3

so 8*2/3*2=16/6

3*3/2*3=9/6

16/6+9/6=25/6

Hope this helps!

3 0
3 years ago
Read 2 more answers
Two friends sold many pieces of furniture and made ​$1550 during their garage sale. They had fifteen more​ $10 bills than​ $50 b
Novosadov [1.4K]

Answer:

The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

n₂ = 5.8

n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

3 0
3 years ago
A movie theater has n rows and m seats in each row. If each ticket costs $5.60, how much do all tickets to one movie cost?
docker41 [41]

Answer:

All Tickets to one movie cost \$5.60 \times m\times n

Step-by-step explanation:

Given:

Number of rows in theater = n

Number of seats in each row = m

Total number of seats in the theater =  Number of rows in theater \times Number of seats in each row= m \times n

Now given each ticket costs = \$5.60

So to find total of all tickets we need multiply each ticket cost by Total number of seats in the theater

Total tickets cost = each ticket cost \times Total number of seats in the theater  = \$5.60 \times m \times n

3 0
3 years ago
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