<h3>
Answer: 16 square units</h3>
Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5
a^2 + b^2 = c^2
3^2 + x^2 = 5^2
9 + x^2 = 25
x^2 = 25-9
x^2 = 16
x = sqrt(16)
x = 4
This is a 3-4-5 right triangle.
The height of the parallelogram is 4 units.
We have enough info to find the area of the parallelogram
Area of parallelogram = base*height
Area of parallelogram = 4*4
Area of parallelogram = 16 square units
Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.
D.) D’(-3,-16)
Trans station is (x-5,y-16)
It 17 but you didn't give me a number line
5th term = a1r^4 where a1 = first term and r = common ratio
so 1/4 = a1 * (1/2)^4
a1 = 1/4 / (1/2)^4 = 4
so the sequence is 4 , 4*1/2, 4*(1/2)^2...
= 4, 2, 1, 1/2, 1/4 .....
Answer:
0
It runs parallel to the z-axis and so has a zero slope
