Answer:
2+7895 hfcygshcrnagdjdhxr
There are 4 possible letters to start with.
The pass word is 3 letters long.
The first letter can be A, B, C, D = 4 different letters.
The 2nd letter can be 4 - 1 = 3 letters ( Can't have repeats)
The 3rd letter can be 3-1 = 2 letters ( no repeats)
Number of possible passwords = 4 x 3 x 2 = 24
He was not supposed to simplify. He could have multiplied straight across and got 12/63 and he would simplify that which would be 4/21 im thinking
Answer:
Polynomial Expression.
Step-by-step explanation:
