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jenyasd209 [6]
8 months ago
15

What is the solution set of x2 + 5x- 5 = 0? oss-355 S +385 o sus S* o {stay -S-345 , 30 O S=5+375 5+3/5 2 0 --375 -5 +385 2

Mathematics
1 answer:
jolli1 [7]8 months ago
6 0

Given the quadratic equation:

x^2+5x-5=0

Using the general solution for quadratic equations:

ax^2+bx+c=0\Rightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

From the problem, we identify:

\begin{gathered} a=1 \\ b=5 \\ c=-5 \end{gathered}

Then:

x=\frac{-5\pm\sqrt{25+20}}{2}=\frac{-5\pm3\sqrt{5}}{2}

And the solution set is:

\lbrack\frac{-5-3\sqrt{5}}{2},\frac{-5+3\sqrt{5}}{2}]

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In triangle FGH, angle G is 30 degrees and angle H is 100 degrees. What is the measure of angle F? * 1 point 50 degrees 70 degre
serg [7]
Mark brainlist please!

Answer is 50 degrees

Since,

measure of angle F + measure of angle G + measure of angle H = 180

30 + 100 + measure of angle F = 180

Measure of angle F = 180 - 130

Measure of angle F = 50 degrees
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2 years ago
How many variables are in this equation:<br> 2y + 5 = 5n
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Answer:

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2 years ago
Let f(y) = y^4 - 3y^3 + y - 3 and g(y) = y^3 + 7y^2 - 2. Find f(y) + g(y). Write your answer as a polynomial with terms of decre
Anarel [89]
<h3>Answer:   y^4 - 2y^3 + 7y^2 + y - 5</h3>

Work Shown:

h(y) = f(y) + g(y)

h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)  

h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2  

h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)

h(y) = y^4 - 2y^3 + 7y^2 + y - 5

This is a fourth degree polynomial (aka quartic).

5 0
2 years ago
Please help me with this sum​
dimulka [17.4K]

Answer:

3950÷5=790 (790×5=3950)

1914÷6=319 (319×6=1914)

give a try for next sums

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