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3 years ago

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What are the domain and range of the function on the graph?

2 answers:

Rainbow [258]3 years ago

4 0

we know that

The domain of the function of the graph is the interval-----> (-∞,∞)

that means

All real numbers

The range of the function of the graph is the interval-----> (0,∞)

that means

$y> 0$ -----> all real numbers greater than zero

therefore

<u>the answer is the option D</u>

The domain includes all real numbers, and the range is y > 0

Vsevolod [243]3 years ago

3 0

Answer:

D) The domain includes all real numbers, and the range is y > 0.

Step-by-step explanation:

Given : Graph .

To find : What are the domain and range of the function on the graph.

Solution :

Domain : The domain is the set of all possible x-values .

Range : The range of a function is the complete set of all possible resulting values of the dependent variable y.

We can see from the graph , x values includes all real numbers and range ( y values greater than 0 because graph line is not intersect at 0 .

Therefore, D) The domain includes all real numbers, and the range is y > 0.

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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra

Nana76 [90]

The length of BC is $4 \sqrt{5}$ .

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

<u>Leg rule of geometric mean theorem:</u>

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

$\Rightarrow 16\times 5 = x\times x$

$\Rightarrow 80= x^2$

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Taking square root on both sides.

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$\Rightarrow \sqrt{4^2\times 5} = \sqrt{x^2}$

square and square roots get canceled, we get

$\Rightarrow 4\sqrt{ 5} = x$

The length of BC is $4 \sqrt{5}$ .

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