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1 year ago

What is the common ratio between successive terms in the sequence 2 - 4 8 -16 32 -64

Mathematics

1 answer:

Dmitriy789 [7]1 year ago

3 0

Answer:

The common ratio of the sequence is -2.

Step-by-step explanation:

To find the common ratio of a sequence, we divide each term by it's predecessor.

-4/2 = 8/-4 = -16/8 = ... = -2

The common ratio of the sequence is -2.

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Expand for brainliest pls

My name is Ann [436]

$x(13 - x) [ multiply\: both \:terms\: with\: x]\\ = 13x - {x}^{2}$

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3 years ago

Which is the best explanation ?

kipiarov [429]

Answer:

Step-by-step explanation:

The student hasn't finished the factoring yet.

<u>He still needs the step:</u>

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3 years ago

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I’m having a bit issue with them can someone please help?

Snezhnost [94]

You were on the right track. Here are two ways to go about it.

• By definition of conditional probability,

Pr[A | B] = Pr[A and B] / Pr[B]

Out of the total 100 participants in the survey, there are 18 people that both have a positive attitude and are over 35, so

Pr[positive and over 35] = 18/100

Out of the 100 pariticipants, 40 are over 35, so

Pr[over 35] = 40/100

Then the conditional probability you want is (18/100) / (40/100) = 18/40 = 9/20.

• There are 40 people over 35 in the survey. You want the probability that someone randomly chosen from this group has a positive attitude, of which there are 18. Hence the probability is 18/40 = 9/20.

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2 years ago

What is the equivalent expression for 2/3÷4/5

Aliun [14]

2/3÷4/5
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10/12
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Hope this helps :)

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3 years ago

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Find the derivatives of the following implicit function

ddd [48]

Answer:

$\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

Step-by-step explanation:

$3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)$

$\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

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3 years ago