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Lera25 [3.4K]
3 years ago
12

In a coordinate plane, triangle ABC has vertices A(-4,5), B(-4,-4), and C(3.-4). Find the perimeter of triangle ABC to the neare

st tenth. A)27.0 units B)27.4 units C)26.1 units D)25.3 units
Mathematics
1 answer:
Aneli [31]3 years ago
6 0
The perimeter of the triangle is B) 27.4
Please let me know if you need an explanation.
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Lelu [443]

Answer:

Surface area : 143.1

Step-by-step explanation:

Ok so first,

Bottom : 35.1 ft

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Right side : 36

Left side : 36

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3 years ago
Convert the angle 0=345
xenn [34]
The answer would be 0
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4 years ago
Consider parallelogram VWXY below.
olchik [2.2K]

note:Parallelogram WXYZ not VWXY & I will answer the questions in the image b'cos I don't get your question.

Answers:

a.(i.)Slope of line YZ = 4/5

(ii.)Line adjacent line YZ is line YX,slope of YX =5/4

b.(i.)Length of line YZ =√41 units

 (ii.)Length of line YX =√41 units

c.WXYZ is a rhombus.

Step-by-step explanation:

a.Slope=gradient(m)=(y₂-y₁)/(x₂-x₁)

(i.)m of line YZ=(y₂-y₁)/(x₂-x₁) where Y(-6,-1) & Z(-1,3)

(I believe you know what the y₂,y₁,x₂ & x₁ stand for.)

So m=(y₂-y₁)/(x₂-x₁),=(3-(-1))/(-1-(-6) =(4)/(5)=4/5

∴m of line YZ is 4/5

(ii.)m of line YX=(y₂-y₁)/(x₂-x₁) where Y(-6,-1) & X(-2,4)

So m=(y₂-y₁)/(x₂-x₁),=(4-(-1))/(-2-(-6) =(5)/(4)=5/4=1.25

∴m of line YX is 5/4

b.(i.)To find the length of line YZ,we have to express it as column vector YZ.

Vector YZ=OZ-OY,Z-Y=(-1,3)-(-6,-1)=(5,4)

Length=√x² plus y²=√5² plus 4²=√25 plus 16=√41 units

∴The length of line YZ is √41 units.

(ii.)To find the length of line YX,we have to express it as column vector YZ.

Vector YX=OX-OY,X-Y=(-2,4)-(-6,-1)=(4,5)

Length=√x² plus y²=√4² plus 5²=√16 plus 25=√41 units

∴The length of line YX is √41 units.

c.WXYZ is a rhombus.

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You MADE 82 out of 100 free-throws during practice. What is your shooting percentage?
alexgriva [62]

Answer:

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Step-by-step explanation:

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In the first step when the student did -2x-3 they didn’t make the sign positive. It should be 4=-2+6, not 4=-2-6
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