The first expression could be written as 3x + 12 and the second could be written as 2x + 6.
In order to find these, count the number of x's you see in each question. Then use that number as the coefficient to x in your statement. The first problem has 3 and the second has 2.
Then add the numbers of 1's together to get the constants at the end of the expressions. The first has 12 and the second has 6.
9514 1404 393
Answer:
12,00,000 rupees
Step-by-step explanation:
The fraction originally intended for each son was ...
(1/3)(1 -2/5) = 1/3(3/5) = 1/5
The fraction each son actually received was ...
(1 -1/6)(1/5) = (5/6)(1/5) = 1/6
The difference in these amounts as a fraction of the original distribution is ...
1/5 - 1/6 = (6/30) -(5/30) = 1/30
Then the original distribution is 30 times this difference:
30×40000 rupees = 12,00,000 rupees
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<em>Additional comment</em>
Originally-intended distribution (rupees):
- wife: 4,80,000
- each son: 2,40,000
Actual distribution:
- brother: 2,00,000
- wife: 4,00,000
- each son: 2,00,000
1,00,000 = 1 lakh
Answer:
The upper one is 8, the lower one is 6
The answer is A or c I’m probs wrong
