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ozzi
1 year ago
12

A company makes Japanese-style lunch boxes called bento boxes. Each bento box is a cube with-foot-long edges. The company ships

the bento boxes in a container in the shape of a rectangular prism that measures 7/2 feet by 3/2 feet by 3/2 feet. A manager correctly finds the volume of the container using a formula. An employee double-checks the calculation by packing the container full of bento boxes. Use the drop-down menus to explain how both volume calculations compare. Click the arrows to choose an answer from each menu. The manager can find the volume of the container using the formula Choose... lwh, 2(lw+lh+wh), or l + w + h The employee correctly determines that the container can be filled with Choose... 7 layers of 21, 3 layers of 21, 7 layers of 3, or 3 layers of 10 bento boxes. He can find the volume of the container by multiplying the number of bento boxes that fill the container by the Choose... base area, volume, or edge lenghts of one bento box. The volume found by using the formula is of bento boxes in the container. Y Choose... equal to, less than, or greater than ▼ the volume of the total number​
Mathematics
1 answer:
MatroZZZ [7]1 year ago
7 0

The volume of the total number of bento boxes is 63/8 ft³.

<h3>How to calculate the volume?</h3>

It should be noted that the volume of the container will be: found by multiplying the length by the width by the height.

This will be:

= length × width × height.

.

= 7/2 × 3/2 × 3/2

= 63/8

Therefore, the volume of the total number of bento boxes is 63/8 ft³.

Learn more about volume on:

brainly.com/question/463363

#SPJ1

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We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

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We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

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P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

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P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

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