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2 years ago

I AM STUCK AND NEED HELP will give 30 points

Mathematics

2 answers:

Aleks04 [339]2 years ago

8 0

the answer is infinite solution

Masteriza [31]2 years ago

3 0

<h3>Answer: A) infinite solutions</h3>

Explanation:

Despite there only being one line shown, there are actually two lines here. One just happens to be directly on top of the other.

We can see this by noting that 2y = 3x-1 turns into 4y = 6x-2 when we multiply both sides by 2. Multiplying both sides by the same number keeps the same equation, so that's why we have identical graphs.

The two identical graphs intersect each other infinitely many times, leading to infinitely many solutions. All solutions are (x,y) points on the blue line. Two such solutions are (1,1) and (3,4). All solutions are of the form $\left(x, \frac{3x-1}{2}\right)$

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In the triangle below, what ratio represents cot Y?

arsen [322]

TanY=y/x

cotY=1/tanY

cotY=x/y

7 0

3 years ago

A rectangular garden has a walk around it of width x. The garden is 20 ft by 15 ft. Write a function representing the combined w

kodGreya [7K]

Answer: A(x) = 15 ft + 2x

EXPLANATION

Given,

The dimension of the rectangular garden is 20 ft by 15 ft.

Dimension of a rectangle is written as Length by Width

This implies that,

Length of the garden = 20 ft

Width of the garden = 15 ft

The garden has a walk around it of width x.

The combined width of the garden = Width of garden + 2x

[we are adding twice the width of the walk because it is around the garden (this means it will add to the width of the garden on both the left and right sides)]

Combined width of the garden, A(x) = Width of garden + 2x

Since width of the garden = 15 ft

A(x) = 15 ft + 2x

5 0

3 years ago

1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.

kkurt [141]

1. The values of p and q are: p=31 and q= 4

2. B(11, 29/5)

Further explanation:

<u>1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.</u>

Given:

M = (15. 1)

(x1, y1) = (p, -2)

(x2, y2) = (-1, q)

The formula for mid-point is:

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M \\Putting\ the\ values\\(\frac{p-1}{2} , \frac{-2+q}{2}) = (15,1)\\Putting\ realtive\ values\ equal\\\frac{p-1}{2} = 15\\p-1 = 15(2)\\p-1 = 30\\p = 30+1\\p = 31\\\frac{-2+q}{2} =1\\-2+q = 2(1) \\-2+q = 2\\q = 2+2 \\q =4$

Hence,

p=31

q=4

<u>2. M is the midpoint of the straight line joining point A (3. 1/5) to point B.If m has coordinates (7. 3), find the coordinates of B.</u>

Here,

(x1,y1) = (3, 1/5)

(x2, y2) = ?

M(x,y) = (7,3)

Putting values in the formula of mid-point

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M\\(\frac{3+x_2}{2} , \frac{1/5+y_2}{2}) = (7,3)\\\frac{3+x_2}{2} = 7\\3+x_2 = 7*2\\3+x_2 = 14\\x_2 = 14-3\\x_2 = 11\\\frac{\frac{1}{5}+y_2}{2} = 3\\{\frac{1}{5}+y_2} = 3*2\\{\frac{1}{5}+y_2} = 6\\y_2 = 6 - \frac{1}{5}\\y_2 = \frac{30-1}{5}\\y_2 = \frac{29}{5}$