I AM STUCK AND NEED HELP will give 30 points
2 answers:
<h3>Answer: A) infinite solutions</h3>
Explanation:
Despite there only being one line shown, there are actually two lines here. One just happens to be directly on top of the other.
We can see this by noting that 2y = 3x-1 turns into 4y = 6x-2 when we multiply both sides by 2. Multiplying both sides by the same number keeps the same equation, so that's why we have identical graphs.
The two identical graphs intersect each other infinitely many times, leading to infinitely many solutions. All solutions are (x,y) points on the blue line. Two such solutions are (1,1) and (3,4). All solutions are of the form
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We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru