Question

What will be the fish population in 11 years? Round your answer to the nearest whole number?

Answer 1

Given:

t = 11 years

$P(t)=625\ln (2t+e)$

Asked: What will be the fish population in 11 years?

Solution:

In order to solve the fish population in 11 years, we will substitute 11 to t.

$\begin{gathered} P(t)=625\ln (2t+e) \\ P(11)=625\ln (2\cdot11+e) \\ P(11)=625\ln (22+2.718281828) \\ P(11)=625\ln (24.718281828) \\ P(11)=625\cdot3.207543125 \\ P(11)=2004.714453 \end{gathered}$

ANSWER:

There will be 2005 fishes in 11 years.