To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
Answer:
x = 15°
Step-by-step explanation:
(5x-15) + 75 + 3x = 180
8x + 60 = 180
8x = 120
x = 15°
Answer:
The best option is c
Step-by-step explanation:
The same textbooks contains a total of 848 pages . Which represent the total number of pages , y , of any number of the same textbooks , x.
The number of same text book = x
Each of this textbook contains a total of 848 pages .
The total number of pages can be computed as
y = 848x
for 4 same text book
y = 848 × 4 = 3392 pages
for 3 same text book
y = 848 × 3= 2544 pages
for 7 same text book
y = 848 × 7 = 5936 pages
for 8 same text book
y = 848 × 8 = 6784 pages
for 11 same text book
y = 848 × 11 = 9328 pages
Answer:
the top one, (-1,3)
Step-by-step explanation:
