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Aloiza [94]
1 year ago
15

19 A trapezoid has an area of 216 square

Mathematics
1 answer:
Vanyuwa [196]1 year ago
6 0

Answer:

A)18in.

Step-by-step explanation:

Given,

A trapezoid Area= 216 sq

The length of its longer base=2x

The length of its shorter base= x

Height of Trapezoid = 8in

Area of Trapezoid= 1/2h(a+b)

216=1/2 x 8(2x+x)

216=4(2x+x)

216/4=3x

54=3x

54/3=x

18=x

Length of shorter base=18

Length of longer base=2x18=36

Hence, the length of the shorter base is 18in

Option A) is correct

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Answer:

Step-by-step explanation:

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RHS  b-a = -6 - (- 9) =  -6 +9 = 3

as LHS not equal to RHS

a-b not equal to b-a

Thus proven

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A farmer planted 32 rows of sweet peppers. Each row had 16 sweet pepper plants. How many plants does he have ALTOGETHER​
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Find the surface area of the following figure with the given dimension
andrezito [222]

Answer:

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Step-by-step explanation:

Given

The attached figure

Required

The surface area

This is calculated as:

SA = 2(LW + LH + HW)

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2 years ago
Write as an algebraic expression. "The difference between a number and -13
melisa1 [442]
n - (-13)
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2 years ago
Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
2 years ago
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