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Morgarella [4.7K]
2 years ago
14

A tire manufacturer knows that 5% of tires contain a defect, and the presence of a defect is independent from tire to tire.

Mathematics
2 answers:
saul85 [17]2 years ago
5 0

The probability that if 5 tires are inspected, exactly 2 have a defect is 0.021

<h3>How to calculate the probability</h3>

The given parameters are:

p = 5\% --- the proportion that contains defect

n =5 --- the sample size

r =2 -- the selected sample

The probability is then calculated as:

P(x =r) = ^nC_r * p^r * (1 - p)^{n-r}

So, we have:

P(x =2) = ^5C_2 * (5\%)^2 * (1 - 5\%)^{5-2}

P(x =2) = 10 * (5\%)^2 * (1 - 5\%)^3

P(x =2) = 0.021

Hence, the probability that if 5 tires are inspected, exactly 2 have a defect is 0.021

Read more about probabilities at:

brainly.com/question/15246027

marta [7]2 years ago
5 0

N=5

K=2

P=0.05

CoE= 10

10 x (0.05)^2 x (0.95)^3

10 x (0.0025) x (0.8573) = 0.0214

feeling stupld now huh vbofill82

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Step-by-step explanation:

to solve for z in the -p(d+z)=-2z+59 expression, we would open the bracket and then evaluate for the exact value of z

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