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krek1111 [17]
1 year ago
9

In a manufacturing process, a random sample of 36 bolts has a mean length of 3 inches with a standard deviation of .3 inches. Wh

at is the 99 percent confidence interval for the true mean length of the bolt?
Mathematics
1 answer:
Liula [17]1 year ago
3 0

The 99 percent confidence interval for the true mean length of the bolt is CI = (2.8712, 3.1288)

<h3>How to find the confidence interval?</h3>

Confidence Interval is used to tell us the degree of certainty or uncertainty that is existent in a sampling method.

The general formula for confidence interval is;

CI = x' ± z(s/√n)

where;

x' is sample mean

z is z-score at confidence level

s is sample standard deviation

n is sample size

We are given;

sample size; n = 36

Sample mean; x' = 3 inches

standard deviation; s = 0.3 inches

confidence level = 99%

z at 99% CL = 2.576

Thus;

CI = 3 ± 2.576(0.3/√36)

CI = 3 ± 0.1288

CI = (2.8712, 3.1288)

Read more about Confidence Interval at; brainly.com/question/17097944

#SPJ1

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3 years ago
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Sienna used the scale drawing above to create a pool that is 14 ft wide x 22 ft long. She then decided to make pool with a final
Bond [772]

A scale factor allows a shape to be changes into another shape by changing  the linear dimensions to the multiples of the initial dimension and a constant

The expression that finds the change in scale factor for the longer pool with a final length of 33 ft. Sierra is building is the option;

  • \dfrac{2 \, ft.}{3 \, ft.}

Reason:

Known parameters are;

Dimensions of the pool created = 14 ft. wide × 22 ft. long

Final length of the pool = 33 ft.

Let <em>x</em> represent the length of the drawing using the initial scale factor, we have;

  • The \ initial \ scale \ factor = \dfrac{22 \, ft.}{x \, in.}

The scale factor of the drawing following a final length of 33 ft. is therefore;

  • New \ scale \ factor = \dfrac{33 \, ft.}{x \, in.}

The change in scale factor is given as follows;

Change \ in \ scale \ factor = \dfrac{Initial \, scale \, factor}{Final \, scale \, factor}

Therefore;

  • Change \ in \ scale \ factor = \frac{\left( \dfrac{22 \, ft.}{x \, in.} \right)}{\left( \dfrac{33 \, ft.}{x \, in.} \right)} = \dfrac{2 \, ft.}{3 \, ft.}

Learn more here;

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8 0
3 years ago
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2x<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-%2014x%20%2B%2024" id="TexFormula1" title="2x^{2} - 14x + 24" alt="2x^{2} -
choli [55]
What are we supposed to solved X or Y, what kind of answer need be for specific please
4 0
2 years ago
What is the radius of a circle whose equation is x2 + y2 – 10x + 6y + 18 = 0?
antoniya [11.8K]
You can do this by completing the square on x and y terms:

  x^ - 10x + y^2 + 6y + 18 = 0

  (x - 5)^2 -25 + (y + 3)^2 - 9 + 18 = 0

  (x - 5)^2  + (y + 3)^2 = -18 + 9 + 25  =  16


so radius = sqrt16  = 4 answer
5 0
3 years ago
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How to find (c,d,e)<br>Please do a step by step working.Thank you.
Natasha2012 [34]
(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
                   \frac{t + 1}{2} = y
Answer for (a): g^{-1}(t) =  \frac{t + 1}{2}

(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y: y =\frac{t - 3}{4}

Answer for (b): h^{-1}(t) = \frac{t - 3}{4}

(c)
g^{-1} ( h^{-1}(t)) =  g^{-1} (\frac{t - 3}{4})
replace all t's in the g^{-1}(t) equation with \frac{t - 3}{4}
 g^{-1} (\frac{t - 3}{4}) = \frac{ \frac{t-3}{4} + 1}{2}
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Answer for (c): g^{-1} ( h^{-1}(t)) = \frac{t + 1}{8}

 (d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1

(e)
h(g(t)) = 8t - 1
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   t = 8y - 1
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Answer for (e): inverse of h(g(t)) = \frac{t + 1}{8}
 
























8 0
3 years ago
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