Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer:
Step-by-step explanation:
Let the numbers be x and y
<h3>Given condition:</h3>x + y = 48 --------(1)
y = 7x -------------(2)
Put Eq. (2) in (1)
x + 7x = 48
8x = 48
Divide 8 to both sides
x = 48/8
<h3>x = 6</h3>Put x = 6 in Eq. (2)
y = 7 (6)
<h3>y = 42</h3>Answer:
x + y are either 2 or 4
Step-by-step explanation:
conclusion x + y = 2 OR 4
