Question

Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Answer 1

Answer:

  D.  Minimum at (3, 7)

Step-by-step explanation:

We can add and subtract the square of half the x-coefficient:

  y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2

  y = (x -3)^2 +7 . . . . . simplify to vertex form

Comparing this to the vertex for for vertex (h, k) ...

  y = (x -h)^2 +k

We find the vertex to be ...

  (3, 7) . . . . vertex

The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.