The graph of g(x) obtained from the horizontal shrink, reflection and translation of f(x) by a factor of 16, across the x–axis and 2 units downwards is given by the function;
Please see the attached graph of g(x)
<h3>What is a transformation of a function?</h3>The transformation of the graph of a function is the shrinking, stretching, reflecting or translating of the graph of the function
The given function is f(x) = x²
The graph of g(x), which is a horizontal shrink by a factor of 16, a reflection across the x–axis and a vertical shift of 2 units downwards, is obtained from the function, g(x) = -f(16•x) - 2 = -(16•x)² - 2
Therefore;
Please find attached the graph of g(x) created with Sheets
Learn more about the transformation of a function here:
#SPJ1
Initial speed (v) = 1.9m/s
Final speed (u) = 3.8m/s
Time (t) = 11 s
<h2>Formula Used :-</h2>(a = acceleration)
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(putting the value of v, u and t from above)
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Therefore, the acceleration rate = 0.17m/s.
The given functions are:
The domain is the set of all possible values that the independent variable (x) can take.
The range is the set of values that the function will take.
For these functions, the domain is all real numbers since they both will work with any positive or negative number (-∞,∞). Thus, the range is the same, all real numbers (-∞,∞).
But, for the purpose of the question let's analyze the interval you took for the table of values:
For f(x) function, you take x-values from -3 to 3, then the domain in this interval is [-3,3] and the range is the output values (f(x)), then the range is [-7,11].
For g(x) function, you take x-values from -7 to 11, then the domain in the interval is [-7,11] and the range (the g(x) values obtained) is [-3,3].
As can be noticed, in the interval the domain of the f(x) functions is the same as the range of the g(x) function, and the domain of the g(x) function is the same as the range of f(x) function. This happens because g(x) is the inverse function of f(x).
Answer:
1000
Step-by-step explanation:
see how to solve in pic
