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Mama L [17]
1 year ago
6

Suppose we have a bottomless bag of 3 different kinds of balls: blue, green, and red. How many possibilities are there to choose

3 balls and arrange them in a line.
Mathematics
1 answer:
sleet_krkn [62]1 year ago
6 0

The number of possibilities that are there to choose 3 balls is 6.

<h3>How to illustrate the information?</h3>

From the information, we have a bottomless bag of 3 different kinds of balls: blue, green, and red.

The number of possibilities that are there to choose 3 balls will be:

= 3!

= 3 × 2 × 1

= 6 possibilities.

Therefore, the number of possibilities that are there to choose 3 balls is 6.

Learn more about permutations on:

brainly.com/question/4658834

#SPJ1

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On Fridays, Jerry stops at Steak &amp; Taco Shack before he goes home. This week
Vika [28.1K]

Answer:

Steak sandwich = x = 4

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Taco salad = z = 2

Step-by-step explanation:

Let :

Steak sandwich = x

Cheese fries = y

Taco salad = z

This week:

x + 2y + 2z = 11.50 - - - - (1)

Last week :

2x + 3y + z = 15.25 - - - (2)

Two weeks ago :

x + 4y + z = 13 - - - - - (3)

Taking (1) and (2)

x + 2y + 2z = 11.50 ___(1)

2x + 3y + z = 15.25 ___(2)

Multiply (1) by 2 and (2) by 1 and subtract

2x + 4y + 4z = 23

2x + 3y + z = 15.25

_______________

y + 3z = 7.75 - - - - (4)

Taking (2) and (3)

2x + 3y + z = 15.25 - - (2)

x + 4y + z = 13 - - - - - (3)

Multiply (2) by 1 and (3) by 2 and subtract

2x + 3y + z = 15.25

2x + 8y + 2z = 26

______________

-5y - z = - 10.75 - - - - - (5)

Lets solve (4) and (5)

y + 3z = 7.75 - - - - (4) - - - multiply by 5

-5y - z = - 10.75 - - - - - (5) - - - multiply by 1

Then add the result :

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____________

14z = 28

z = 28 / 14

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To find y ; put z = 2 in (4)

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From equation 3 ;

x + 4y + z = 13 - - - - - (3)

x + 4(1.75) + 2 = 13

x + 7 + 2 = 13

x + 9 = 13

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x = 4

Hence,

Steak sandwich = x = 4

Cheese fries = y = 1.75

Taco salad = z = 2

5 0
3 years ago
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