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Mama L [17]
1 year ago
6

Suppose we have a bottomless bag of 3 different kinds of balls: blue, green, and red. How many possibilities are there to choose

3 balls and arrange them in a line.
Mathematics
1 answer:
sleet_krkn [62]1 year ago
6 0

The number of possibilities that are there to choose 3 balls is 6.

<h3>How to illustrate the information?</h3>

From the information, we have a bottomless bag of 3 different kinds of balls: blue, green, and red.

The number of possibilities that are there to choose 3 balls will be:

= 3!

= 3 × 2 × 1

= 6 possibilities.

Therefore, the number of possibilities that are there to choose 3 balls is 6.

Learn more about permutations on:

brainly.com/question/4658834

#SPJ1

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Question 2
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The domain of the function is x ≤ 6.88

The domain of the function is y ≤ 20

<h3>Domain and Range</h3>
  • These are input and output values for which the function exists

Given the function of x expressed as:

y = 3.5x + 2.8

The domain occurs at the point where 3.5x + 2.8 ≤ 20

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