Question

Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points in simplest radical form. (-8,-6) and (-5,1)

Answer 1

We have the following:

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

replacing:

$\begin{gathered} d=\sqrt[]{(_{}-5-(-8)_{})^2+(-6-1_{})^2} \\ d=\sqrt[]{3^2+7^2} \\ d=\sqrt[]{9+49}=\sqrt[]{58} \end{gathered}$

now, the graph

leg 1 = 3

leg 2 = 7

hypotenuse = 7.61