Question

let P = (x,y) and Q = (1, 5). suing formula that you know for slope write an eqation in these terms of coordinates that says that the slope of line PQ is 3. show how this slope equation can be rewritten in the form y - 5 =3 (x -1).this linear eqation is said to be in point-slopr form. explain the terminology find coordinates for three diffrent points p that fit this equation

Answer 1

The equation of a line in point-slope form is y - 5 = 3( x - 1).

What is the equation of a line in slope intercept form?

Equation of a line in slope intercept form is y = mx + b, where slope = m and y-intercept = b.The slope of a line is defined as the rate of change of the y-axis with respect to the x-axis.

We know the equation of a line in point-slope form is y - y₁ = m(x - x₁).

Given P = (x,y) and Q = (1,5) or (x₁, y₁).

∴ Equation of a line in point-slope form given (x₁,y₁) = (1,5) and slope(m) = 3 is y - 5 = 3( x - 1).

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