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2 years ago

What's the 100th term of 2,4,6,8,10,12,14

Mathematics

2 answers:

Sidana [21]2 years ago

6 0

Answer:

200

Step-by-step explanation:

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Otrada [13]2 years ago

4 0

Step-by-step explanation:

$a_{100}$ = 2 x $2-1^{100-1}$

200

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Students pass a test it they score 50% or more. the marks of a large number of students were sampled and the mean and standard d

Schach [20]

So we are given that the mean is 42% and the sd (standard deviation) is 8%
Assuming our data is normal we can use the 68-95-99 rule

So one thing you should realize is that 42% + 8% is 50% which is passing. That is one standard deviation higher. So we use:

100 - 68 - 13.5 - 2.35 - 0.15 = 16. That means 16% of students passed the test. Which is terrible. They probably need to hit the books more.

Anyways if you have any question feel free to message me!
Hopes this helps!

3 0

3 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

A number increased by 5 is less than or equal to 26

blagie [28]

Answer:

Equation: x + 5 ≤ 26

Solved: x ≤ 21

3 0

3 years ago

Whats The sum of twice a number x and thrice a number y minus the square of z as an expression

SpyIntel [72]

Answer:

2x+3y-z²

Step-by-step explanation:

twice a number =2x

thrice a number =3x

minus z²

HOPE THIS HELPS!!!

8 0

2 years ago

Read 2 more answers

Find the equation of the linear function represented by the table below in slope-

maria [59]

Answer:

y=2x+1, assuming my change in the reported data was correct.

Step-by-step explanation:

The data for x had one more entry than the values for y. I removed the second "0" so that the x and y points line up, as shown in the attached image. The data indicate a straight line, with a slope of 2 (y increases by 2 for every x increase of 1). The y-intercept is 1, as per the first data point (0,1).

3 0

2 years ago