Can someone help me out

Mathematics

1 answer:

Svetllana [295]3 years ago

5 0

<h3>x intercepts are (-1,0) and (-11,0)</h3>

This can be shortened to "x intercepts are -1 and -11" since in every case, the y value is always 0 for any x intercept. There's no need to state the y coordinate since it's always 0.

We find this by solving (x+1)(x+11) = 0 for x using the zero product property

(x+1)(x+11) = 0

x+1 = 0 or x+11 = 0

x = -1 or x = -11

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<h3>The y intercept is (0,11). </h3>

This is the result of computing y = (0)^2+12(0)+11. Due to how easy it is to work with 0, we basically just erase the (0)^2+12(0) portion and we're left with 11 as our y intercept. This means you can erase the x^2+12x portion of the original equation to get the same result.

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If f(x) = 2x2 + 1, what is f(x) when x = 3?.

kvv77 [185]

Answer:

5/3 is the correct answer

8 0

3 years ago

Graph the line with a slope of 2/5 that goes through (3,1)

Triss [41]

Answer:

$y = \dfrac{2x}{5} - \dfrac{1}{5}$

Step-by-step explanation:

Given:

$\bullet \ \ \text{Slope of line:}\ \dfrac{2}{5} \\\\ \bullet \ \text{Passes through:} \ (3, 1)$

To determine the equation of the line, we will use point slope form.

<u>Formula of point slope form:</u>

→ y - y₁ = m(x - x₁)

Where "x₁" and "y₁" are the coordinates of the point and "m" is the slope.

Substitute the coordinates and the slope:

$:\implies y - 1 = \dfrac{2}{5} (x - 3)$

Simplify the R.H.S:

$:\implies y - 1 = \dfrac{2x}{5} - \dfrac{6}{5}$

Add 1 both sides:

$:\implies y - 1 + 1 = \dfrac{2x}{5} - \dfrac{6}{5} + 1$

Simplify the equation:

$:\implies y = \dfrac{2x}{5} - \dfrac{6}{5} + \dfrac{5}{5}$

$:\implies \boxed{y = \dfrac{2x}{5} - \dfrac{1}{5}}$

<u>Graphing the line on a coordinate plane:</u>

In this case, we are already given a point (3, 1). We can simply plot the y-intercept $[\bold{\frac{-1}{5} }]$ on the coordinate plane. Then, we can draw a straight line through both points. It is suggested that you use a ruler to do so.