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1 year ago

What will happen to the original shape if the scale factor is a less than 1 b greater than 1 C equal to 1?

1 answer:

4 0

Original shape will contract when scale factor is less than 1 , expand when scale factor is greater than 1 and it doesn't change when scale factor is 1

A scale factor is a number that can be used to change the size of any geometrical figure or shape in relation to its original size. It is the ratio of the sizes of the original and dilated figures.

It is denoted by "k"

The magnitude of the scale factor is taken into account, and it cannot be zero. The scale factor has the ability to either increase or decrease the size of an object.

The basic formula for calculating the scale factor of a dilated figure is as follows:

Scale = dimension of preimage / dimension of image

According to the question,

(a) If scale factor is less than 1 , k < 1 then the original shape will contract means It's size will decrease

(b) If scale factor is greater than 1 , then image will enlarge and it would expand

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3 years ago

The number of pollinated flowers as a function of time in days can be represented by the function. f(x)

ratelena [41]

The average increase in the number of flowers pollinated per day between days 4 and 10 is <u>39</u>, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

In the question, we are asked for the average increase in the number of flowers pollinated per day between days 4 and 10, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

To find the average increase in the number of flowers pollinated per day between days 4 and 10, we use the formula {f(10) - f(4)}/{10 - 4}.

First, we find the value of the function $f(x) = (3)^{\frac{x}{2} }$ , for f(10) and f(4).

$f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(10) = (3)^{\frac{10}{2} }\\\Rightarrow f(10) = 3^5 = 243$

$f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(4) = (3)^{\frac{4}{2} }\\\Rightarrow f(10) = 3^2 = 9$

Thus, the average increase

= {f(10) - f(4)}/{10 - 4},

= (243 - 9)/(10 - 4),

= 234/6

= 39.

Thus, the average increase in the number of flowers pollinated per day between days 4 and 10 is <u>39</u>, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

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For complete question, refer to the attachment.

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