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2 years ago

Solve for x. C=x+a/b

Mathematics

1 answer:

marshall27 [118]2 years ago

3 0

Since you are solving for x, you need to isolate x on one side of the equation. Start by subtracting C from both sides.

0 = x + a / b - C

Subtract x from both sides to have it on the left side of the equation.

-x = a / b - C

Make x a positive number by dividing both sides by negative one.

x = - a / b + C

A better way of writing this answer would be: $x=-\frac{a}{b} + C$ .

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Does anyone know this??

blagie [28]

Answer:

x = 38, y = 4

Step-by-step explanation:

Since AB = BC then the triangle is isosceles and the base angles are congruent, that is

∠ DAB = ∠ DCB = 52°

Subtract the sum of the base angle from 180° for ∠ ABC

∠ ABC = 180° - (52 + 52)° = 180° - 104° = 76°

Note that ∠ ABD = ∠ CBD, thus

x = 76 ÷ 2 = 38

BD bisects the side AC, thus DC = AD = 4

Thus y = 4

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3 years ago

If it doesn't give me the perimeter, how do i find x from this? thank you!

Mariulka [41]

The way the angles are labeled tell you that they are all congruent. The two triangles you see here also share the side that joins them. Then by the angle-side-angle postulate, the two triangles are congruent, so x + 23 = 13, or x = -10.

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2 years ago

A plane flew 720 mi with a steady 30 mi/h tailwind. The pilot then returned to the starting point, flying against that same wind

NNADVOKAT [17]

Answer:

Plane's speed is 150 miles/hour

Step-by-step explanation:

Let the plane's airspeed be x

Speed of wind is 30 miles/hour

When a plane flew with the wind , Speed = (x+30)

So, the speed plain with wind on going = (x+30)

Since we are given that on returning plane fly against the wind .

So,When a plane flew against the wind , Speed = (x-30)

So, the speed plain against wind on returning = (x-30)

Distance = 720 miles .

$Time = \frac{Distance}{Speed}$

So, time on going $=\frac{720}{(x+30)}$

Time on returning $=\frac{720}{(x-30)}$

Now we are given that the total time for the whole trip (going + returning) = 10 hours.

So, $\frac{720}{(x+30)}+\frac{720}{(x-30)}=10$

$\frac{720x-21600+720x+21600}{(x+30)(x-30)}=10$

$720x-21600+720x+21600=10(x+30)(x-30)$

$720x+720x=10(x+30)(x-30)$

$1440x=10(x^2 -[30]^2)$

$144x=x^2 -900$

$x^2-144x -900=0$

$x^2-150x+6x -900=0$

$x(x-150)+6(x -150)=0$

$(x-150)(x+6)=0$

$x= 150,x= -6$

So, the plane's speed is 150 miles/hour

4 0

3 years ago

Factor 1/7 out of 1/7x-2/7<br> 1/7x-2/7=1/7(BLANK)

lorasvet [3.4K]

Answer:

Step-by-step explanation:

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