Find the slope and y intercept, then write out the linear equation (y=mx+b) below

Mathematics

1 answer:

AlexFokin [52]1 year ago

5 0

Answer:

y = 2x + 3

Step-by-step explanation:

You can find the slope on the graph by looking at the points. From one point to the next you go Up2Over1.

Up2Over1 is the slope and in actual algebra it is 2/1, which is just 2.

The slope is 2. Fill in 2 in place of m in

y = mx + b

y = 2x + b

Next the y-intercept which is the b, can also be seen on the graph. The y-intercept is where the graph crosses the y-axis. The line crosses the y-axis at 3. Fill in 3 in place of the b.

y = 2x + 3

You might be interested in

Read and answer the question shown below.

ArbitrLikvidat [17]

I would say the answer is A

6 0

3 years ago

HELP PLEASE IT EASY! + no files please!!

NARA [144]

Answer:

GIVEN :-

Ordered pairs given are :-

(2 , -1)
(-5 , 3)
(4 , 3)
(-2 , -3.5)
(0.5 , 1.75)

TO FIND :-

Correct quadrant for each ordered pair.

FACTS TO KNOW BEFORE SOLVING :-

While writing the co-ordinates of a point , its ordered pair is always in the form of ( x , y ) where x = x-coordinate of the point & y = y-coordinate of the point.

In Quadrant 1 , the coordinates of a point is always = ( +x , +y ) because Quadrant 1 lies between the positive side of x-axis & positive side of y-axis.
In Quadrant 2 , the coordinates of a point is always = ( -x , +y ) because Quadrant 2 lies between the negative side of x-axis & positive side of y-axis.
In Quadrant 3 , the coordinates of a point is always = ( -x , -y ) because Quadrant 3 lies between the negative side of x-axis & negative side of y-axis.
In Quadrant 4 , the coordinates of a points is always = ( +x , -y ) because Quadrant 4 lies between the positive side of x-axis & negative side of y-axis.

SOLUTION :-

(2 , -1) is in Quadrant 4 because it's x-coordinate is positive whereas its y-coordinate is negative.
(-5 , 3) is in Quadrant 2 because its x-coordinate is negative but y-coordinate is positive.
(4 , 3) is in Quadrant 1 because both its x-coordinates & y-coordinates are positive.
(-2 , -3.5) is in Quadrant 3 because both its x-coordinates & y-coordinates are negative.
(0.5 , 1.75) is in Quadrant 1 because both its x-coordinates & y-coordinates are positive.