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Elenna [48]
4 years ago
14

The longest side of an acute isosceles triangle is 8 centimeters. Rounded to the nearest tenth, what is the smallest possible le

ngth of one of the two congruent sides? 4.0 cm 4.1 cm 5.6 cm 5.7 cm
Mathematics
2 answers:
antiseptic1488 [7]4 years ago
7 0
Let "x" be the  longest side and "y" be each of <span>remaining sides
If the triangle is </span>аcute<span> then:

</span>y² + y² > x² <span>
2y</span>² > 8²
2y² > 64
y² > 32
y > √32
y > 5.6 ← <span>to the nearest tenth
</span>
This means the length of each of the remaining sides is more than 5.6 cm, so <span>the smallest</span> possible length of one of the two congruent sides is 5.7 cm.
nydimaria [60]4 years ago
3 0

the answer is D) 5.7cm

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3 years ago
a line passes through (1,-5) and(-3,7) write an equation for the line in point slope form rewrite the equation in slope intercep
Marat540 [252]

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Step-by-step explanation:

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