Answer:
60 or 60:1
Step-by-step explanation:
You will have to divide 180 by 3 which is 60 or you can divide 160 / 3 = 60 & divide 3 / 3 = 1.
Answer:
>
4^3 is greater than 6^2
Answer:
There will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days
Step-by-step explanation:
The given parameters are;
The half life of the radioactive substance = 45 days
The mass of the substance initially present = 6.2 grams
The expression for evaluating the half life is given as follows;

Where;
N(t) = The amount of the substance left after a given time period = 1 gram
N₀ = The initial amount of the radioactive substance = 6.2 grams
= The half life of the radioactive substance = 45 days
Substituting the values gives;




The time that it takes for the mass of the radioactive substance to remain 1 g ≈ 118.45 days
Therefore, there will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days.
Answer:
g(5) = - 3
Step-by-step explanation:
you substitute the 5 from the g(5) into your x from your equation so
- x + 2 =
- ( 5 ) + 2 =
- 5 + 2 =
-3