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qwelly [4]
1 year ago
14

Below is the graph of y = |x| . .Translate it to make it the graph of of y=|x-2|+4

Mathematics
1 answer:
sineoko [7]1 year ago
7 0
Explanation

Given a function f(x) we translate the function:

• a units horizontally (a > 0 to the right, a < 0 to the left),

,

• b units vertically (b > 0 up, b < 0 down),

by the transformation:

f(x)\rightarrow g(x)=f(x-a)+b.

In this case, we have:

\begin{gathered} f(x)=|x|, \\ g(x)=|x-2|+4=f(x-2)+4. \end{gathered}

Comparing f(x) and g(x) with the general transformation above, we see that the graph of g(x) is the graph of f(x) translated:

• a = 2 units to the right,

,

• b = 4 units up.

Translating the graph of f(x), we get:

Answer

The translated graph is the graph in red:

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The half-life of a certain radioactive substance is 45 days. There are 6.2 grams present initially. On what day
kvasek [131]

Answer:

There will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days

Step-by-step explanation:

The given parameters are;

The half life of the radioactive substance = 45 days

The mass of the substance initially present = 6.2 grams

The expression for evaluating the half life is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}

Where;

N(t) = The amount of the substance left after a given time period = 1 gram

N₀ = The initial amount of the radioactive substance = 6.2 grams

t_{1/2} = The half life of the radioactive substance = 45 days

Substituting the values gives;

1 = 6.2 \left (\dfrac{1}{2} \right )^{\dfrac{t}{45}

\dfrac{1}{6.2}  =  \left (\dfrac{1}{2} \right )^{\dfrac{t}{45}

ln\left (\dfrac{1}{6.2} \right )  =  {\dfrac{t}{45} \times ln \left (\dfrac{1}{2} \right )

t = 45 \times \dfrac{ln\left (\dfrac{1}{6.2} \right ) }{ln \left (\dfrac{1}{2} \right )} \approx 118.45 \ days

The time that it takes for the mass of the radioactive substance to remain 1 g ≈ 118.45 days

Therefore, there will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days.

3 0
3 years ago
Given g(x)=-x+2, find g(5)
Alona [7]

Answer:

g(5) = - 3

Step-by-step explanation:

you substitute the 5 from the g(5) into your x from your equation so

- x + 2 =

- ( 5 ) + 2 =

- 5 + 2 =

-3

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3 years ago
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