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krek1111 [17]
3 years ago
14

Susan wants to find someone to do yard work at her house for the summer and fall seasons. WeWork charges a $200 fee and then a $

10 per hour fee. Merry mowing charges a $50 fee and then a $20 per hour. What company should she use?
Use graphing elimination or substitution.
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0
200+10h =200 +10 (5) = 250
50 +20h = 50 + 20 (5) = 150
definitely merry's company
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30 points!!!
tino4ka555 [31]
The first one is the 5th tile and the second one is the 3rd tile
4 0
3 years ago
The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli
Triss [41]
(0,2)(-2,0)
slope = (0 - 2) / -2 - 0) = -2/-2 = 1
(0,2)...x = 0 and y = 2
sub and find b, the y int
2 = 1(0) + b
2 = b
equation is : y = x + 2......solid line, means there is an equal sign....shaded below the line means less then....
ur inequality for this line is : y < = x + 2

(0,6)(3,0)
slope = (0 - 6) / (3 - 0) = -6/3 = -2

y = mx + b
slope(m) = -2
(0,6)...x = 0 and y = 6
sub and find b, the y int
6 = -2(0) + b
6 = b

ur equation is : y = -2x + 6....dashed line means there is no equal sign...and shading below the line means less then...
so ur inequality of this line is : y < -2x + 6

In summary, ur 2 inequalities are : y < = x + 2 and y < -2x + 6

4 0
3 years ago
Find the median of the table below. NUMBER OF INCHES 22 24 26 FREQUENCY 3 2 1 3​
Nesterboy [21]

Answer:

24 or 2.5

Step-by-step explanation:

I'm not sure if it was the median of the inches or responses so if it was inches its 24 and if it's the 3 2 1 3 its 2.5

6 0
3 years ago
42/40 into a mixed number is??
SSSSS [86.1K]
Hello there!

So, as we see that 42 is more than the denominator, so, we would have to see by how much it would be over.

40-42=2.

So, sense we have an whole number which would be (1)

Your answer: \boxed{\boxed{\bf 1\frac{2}{40} }}
6 0
3 years ago
Calculus question?
Ann [662]
Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)

Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2   Now differentiate that. It should be much easier.

Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x  I wonder if there's anything else you can do to this. If there is, I don't see it.

I suppose this is possible.
y' = 3/x^(1/2) + 6x

y' = \frac{3 + 6x^{3/2}}{x^{1/2}}

Frankly I like the first answer better, but you have a choice of both.
5 0
3 years ago
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