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What do balloon mortgage and ARM have in common?

VladimirAG [237]

Answer:

In other respects, a balloon mortgage resembles an adjustable rate mortgage (ARM) with an initial rate period equal to the balloon period. A 7-year balloon, for example, is usually compared to a 7-year ARM. Both have a fixed-rate for 7 years, after which the rate will be adjusted.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How do you turn a fraction into a percent

Sladkaya [172]

Divide the numerator by the denominator

4 0

4 years ago

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The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.

nignag [31]

Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

$x^2+6x=-9$

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

$x^2+6x+9=-9+9$

The reason we do this is to create a perfect square binomial on the left:

$(x+3)^2=0$ (obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

$(x+3)^2+0=y$

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.

6 0

3 years ago

Solve the quadratic equation. Show all of your steps. x 2 + 3 x − 5 = 0

AlladinOne [14]

For this case we have the following quadratic equation:

$x ^ 2 + 3x-5 = 0$

Where:

$a = 1\\b = 3\\c = -5$

We look for the solution using the following formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values:

$x = \frac {-3 \pm \sqrt {3 ^ 2-4 (1) (- 5)}} {2 (1)}\\x = \frac {-3 \pm \sqrt {9 + 20}} {2}\\x = \frac {-3 \pm \sqrt {29}} {2}$

Thus, we have two roots:

$x_ {1} = \frac {-3+ \sqrt {29}} {2}\\x_ {2} = \frac {-3- \sqrt {29}} {2}$

Answer:

$x_ {1} = \frac {-3+ \sqrt {29}} {2}\\x_ {2} = \frac {-3- \sqrt {29}} {2}$

3 0

3 years ago

Determine whether line AB and line CD are parallel, perpendicular, or neither. A( 4, 2), B(-3, 1), C(6, 0), D(-10, 8)

Lapatulllka [165]

Answer:

<h2>neither</h2>

Step-by-step explanation:

If AB an CD are parallel, then their slopes are the same.

If AB and CD are perpendicular, then the product of their slopes is equal -1.

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Calculate the both slope:

$A(4,\ 2),\ B(-3,\ 1)\\\\m_{AB}=\dfrac{1-2}{-3-4}=\dfrac{-1}{-7}=\dfrac{1}{7}\\\\C(6,\ 0),\ D(-10,\ 8)\\\\m_{CD}=\dfrac{8-0}{-10-6}=\dfrac{8}{-16}=-\dfrac{1}{2}\\\\=============================$

$m_{AB}\neq m_{CD}$

The line AB and line CD are not parallel

$m_{AB}\cdot m_{CD}=\left(\dfrac{1}{7}\right)\left(-\dfrac{1}{2}\right)=-\dfrac{1}{14}\neq-1$

The line AB and line CD are not perpendicular.

6 0

3 years ago