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Irina18 [472]
3 years ago
13

Help me please asap

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
C is the answer to you question
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If triangle JKL is classified as isosceles, which statement is true?
VMariaS [17]

Answer: At least two sides are congruent

Step-by-step explanation:

Here is the complete question:

If a triangle JKL is classified as isosceles, which statement is true?

a. At least two sides are congruent.

b. Two sides are perpendicular.

c. All three sides are congruent.

d. Two sides are parallel.

An isosceles triangle is a triangle that has at least two sides that are equal. An isosceles triangle has two equal sides and also two equal angles.

An angle is said to be congruent if it has the same angle either in degrees or radians. Such angles don't necessarily have to point in same direction. Therefore, it is true that at least two sides are congruent.

6 0
3 years ago
Please Help! April took out a $900 loan from the bank. At the end of the 5 years, a 3.4%interest rate. How much interest does sh
OleMash [197]

Answer: $30.60

Step-by-step explanation:

multiply 3.4% or 0.034 in decimal form, by 900, and that’s your interest

5 0
3 years ago
Write the equation of a circle with center at (3, -2), which also passes through the point (0, 2).
Airida [17]

\text{The equation of acircle:}\\\\(x-h)^2+(y-k)^2=r^2\\\\(h;\ k)-center\\r-radius\\\\\text{We have center}\ (3,\ -2)\to h=3\ \text{and}\ k=-2.\\\\\text{The radius is the distance between the points} (3,\ -2)\ \text{and}\ (0,\ 2).\\\\\text{The formula of a distance between two points:}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\text{Substitute:}\\\\d=\sqrt{(2-(-2))^2+(0-3)^2}=\sqrt{4^2+(-3)^2}=\sqrt{16+9}\\\\=\sqrt{25}=5\\\\Answer:\ \boxed{(x-3)^2+(y-(-2))^2=5^2\to\boxed{(x-3)^2+(y+2)^2=25}}

3 0
3 years ago
A. how does your equation from 1b relate to the pendulum equation?'
Law Incorporation [45]
What is the equation ? Is there a picture to the question.
8 0
3 years ago
PLEASE HELPPPPPP!!!!! You are performing an experiment to determine how well plants grow under different light sources. Of the 3
PIT_PIT [208]

The probability that a plant in the experiment receives visible or ultraviolet light is 7/10.

<u>Step-by-step explanation</u>:

The total number of plants in the experiment = 30 plants

Plants that receive visible light alone = 12 plants

Plants that receive ultraviolet light alone = 15 plants

Plants that receive both visible and ultraviolet light = 6 plants

<u>step 1</u> :

<em>Probability = No. of required events / Total number</em>

<u>step 2</u> :

P(visible) = 12 / 30

P(ultraviolet) = 15 / 30

P(both) = 6 / 30

<u>step 3</u> :

P(visible  or ultraviolet) = P(visible)  + P(ultraviolet) - P(both)

                                         = 12/30 + 15/30 - 6/30

                                         = 21/30

P(visible  or ultraviolet) = 7/10

8 0
3 years ago
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