Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Yes they are , since they are very common in ones body
Answer:
I'm pretty sure it's +(-6).
Step-by-step explanation:
Basically for these, you find the slope. The slope equation is y1-y2/x1-x2.
Pick two points.
I'll just do (1,15) and (2,9).
15-9/1-2 = 6/-1 = -6.
I don't know if you were taught it this way, but my math teacher always told us that the rate of change had to be positive.
So you'd say the rate of change is +(-6), not -6.
Hope that sorta helped lol
Step-by-step explanation:
the answer is 25%
hope it helps!
