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Andru [333]
1 year ago
7

Find the length of the third side. If necessary, round to the nearest tenth.914

Mathematics
1 answer:
Zina [86]1 year ago
4 0

The given trinagle is a right angle triangle. let the missing side be x. To find x, we would apply the pythagorean theorem which is expressed as

hypotenuse^2 = one leg^2 + other leg^2

From the triangle,

hypotenuse = 14

one leg = 9

other leg = x

Thus, we have

\begin{gathered} 14^2=9^2+x^2 \\ 196=81+x^2 \\ x^2\text{ = 196 - 81 = 115} \\ x\text{ = }\sqrt[]{115} \\ x\text{ = 10.72} \end{gathered}

To the nearest tenth, the length of the third side is 10.7

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Special right triangles: what is the value of x? enter your answer in the box.
tiny-mole [99]
I think you meant to add more to your question (posting the specific problem).
In general, one special right triangle is the <span>45°-45°-90° triangle, in which both legs are congruent and the hypotenuse = √2 * the length of the leg. if you happen to not have the length of the leg, the formula for finding the leg is:  leg = hypotenuse / √2

Another special right triangle is the </span><span>30°-60°-90° triangle. With this kind of triangle the length of the hypotenuse is twice the length of the shorter leg. The length of the longer leg is √3 times the length of the shorter leg.
hypotenuse = 2 * shorter leg
longer leg = √3 * shorter leg</span>
7 0
3 years ago
Help asap please!!!!!!​
Andrews [41]

Step-by-step explanation:

[(-3 × 2 × (-4)] ÷ [-6 × 12]

[3 × 2 × -4] ÷ [-6 × 12]

[6 × -4]/[-6 × 12]

-4/(-1 × 12]

-4/-12

⅓

Option A is wrong

Option B is wrong -9/-18 = ½ not ⅓

Option C is correct = -24/-72 = ⅓

Option D is wrong = 9/-18 = -½ not ⅓

3 0
2 years ago
Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v
blagie [28]
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8 
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span>                          = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
                                   = (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>










3 0
3 years ago
Read 2 more answers
Solve the equation for x. If necessary round to the nearest tenth.<br> x² = 17<br> X=<br> +
Ilya [14]

Answer:

x = 4.1 & x = −4.1

Step-by-step explanation:

x^2 = 17\\

x  =  ±√17

x  =  √17,  −√17

x = 4.1 & x = −4.1

7 0
2 years ago
Reasoning Nolan listed the weights
dmitriy555 [2]

Answer:

the greater is 6.25 ounces because the frequency is 13

8 0
3 years ago
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